document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030921>Question 1030921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular piece of cloth is three times less than 5 it's width. If the perimeter is 38m, what are the dimensions of the piece of cloth?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645726 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = P = 2L + 2W = 38<BR>\n" );
document.write( "We also have L = 3W - 5 (I think that is what you meant.)<BR>\n" );
document.write( "Substituting we get<BR>\n" );
document.write( "2(3W - 5) + 2W = 38<BR>\n" );
document.write( "6W - 10 + 2W = 38<BR>\n" );
document.write( "8W - 10 = 38<BR>\n" );
document.write( "8W = 48<BR>\n" );
document.write( "W = 6 so that <BR>\n" );
document.write( "L = 3(6) - 5 = 13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );