document.write( "Question 1030976: A motorist traveled from Town A to Town B. After traveling one third of the distance for the journey at an average speed of 45 km/h, he continued to travel another 480 km to reach Town B. If his average speed for the entire journey was 54 km/h, what was his average speed for at least two thirds of the distance? \n" ); document.write( "
Algebra.Com's Answer #645717 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A motorist traveled from Town A to Town B. \n" ); document.write( " After traveling one third of the distance for the journey at an average speed of 45 km/h, he continued to travel another 480 km to reach Town B. \n" ); document.write( " If his average speed for the entire journey was 54 km/h, what was his average speed for at last two thirds of the distance? \n" ); document.write( ": \n" ); document.write( "From the information given we know the first third distance was half the distance of the last two thirds: 480/2 = 240km \n" ); document.write( "The total dist: 240 + 480 = 720km \n" ); document.write( ": \n" ); document.write( "let s = speed for the last 2/3 dist \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Time at 45 + time at s = total time \n" ); document.write( " \n" ); document.write( "multiply by the least common denominator, 270s \n" ); document.write( "270s* \n" ); document.write( "Cancel the denominators \n" ); document.write( "6s(240) + 270(480) = 5s(720) \n" ); document.write( "1440s + 129600 = 3600s \n" ); document.write( "129600 = 3600s - 1440s \n" ); document.write( "129600 = 2160s \n" ); document.write( "s = 129600/2160 \n" ); document.write( "s = 60 km/hr for final 2/3 of the trip \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "See if that checks out \n" ); document.write( " \n" ); document.write( "5.33 + 8 = 13.33 hrs \n" ); document.write( " |