document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030919>Question 1030919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers differ by 8. If one half the larger is added to one fourth the smaller, the resulting sum is 22. Find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645711 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the smaller one, x.  Then the larger one is x+8.  Then we write<BR>\n" );
document.write( "(1/2)(x+8) + (1/4)x = 22<BR>\n" );
document.write( "Now solve...multiply everything by 4 to clear fractions...<BR>\n" );
document.write( "2(x+8) + x = 88<BR>\n" );
document.write( "2x + 16 + x = 88<BR>\n" );
document.write( "3x + 16 = 88<BR>\n" );
document.write( "3x = 72<BR>\n" );
document.write( "x = 24<BR>\n" );
document.write( "x+8 = 32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );