document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030922>Question 1030922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John is 5 years more than six times older than Jude. The sum of their ages is 33. Find their ages.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645710 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the ages of John and Jude, j and d.  Then we write<BR>\n" );
document.write( "j = 5 + 6d  and <BR>\n" );
document.write( "j + d = 33<BR>\n" );
document.write( "Now substitute the first one into the second...we get<BR>\n" );
document.write( "(5+6d) + d = 33<BR>\n" );
document.write( "5 + 7d = 33<BR>\n" );
document.write( "7d = 28<BR>\n" );
document.write( "d = 4  (Jude)<BR>\n" );
document.write( "which means<BR>\n" );
document.write( "j = 29  (John)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );