document.write( "Question 1030948: 3(2^x) = 49 \n" ); document.write( "

Algebra.Com's Answer #645702 by Alan3354(69443) $\"\"$ $\"About$

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3(2^x) = 49
\n" ); document.write( "2^x = 49/3
\n" ); document.write( "x*log(2) = log(49/3)
\n" ); document.write( "x = log(49/3)/log(2)
\n" ); document.write( "x =~ 4.029747
\n" ); document.write( " \n" ); document.write( "

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