document.write( "Question 1030948: 3(2^x) = 49 \n" ); document.write( "
Algebra.Com's Answer #645700 by fractalier(6550)\"\" \"About 
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To solve this
\n" ); document.write( "3(2^x) = 49
\n" ); document.write( "let us divide by 3 and take the log of each side
\n" ); document.write( "2^x = 49/3
\n" ); document.write( "ln 2^x = ln (49/3)
\n" ); document.write( "x ln 2 = ln (49/3)
\n" ); document.write( "x = ln(49/3) / ln 2 = 4.02975
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