document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030962>Question 1030962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1) and (8,-2) find the coordinates of P.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645680 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> he coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1) and (8,-2) find the coordinates of P.<BR>\n" );
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document.write( "P = (k,2k)<BR>\n" );
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document.write( "Distance from (-3,1):<BR>\n" );
document.write( "sqrt[(k+3)^2+(2k-1)^2]<BR>\n" );
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document.write( "Distance from (8,-2)<BR>\n" );
document.write( "sqrt[(k-8)^2+(2k+2)^2]<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(k+3)^2+(2k-1)^2 = (k-8)^2+(2k+2)^2<BR>\n" );
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document.write( "Solve for \"k\" and \"2k\"<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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