document.write( "Question 1030953: If a certain two digit number is divided by sum of its digits the quotient is 7 and remainder is 3. if the digits are interchanged and resulting no is divided by positive difference of digits the quotient is 8 and remainder is 1. find the number \n" ); document.write( "
Algebra.Com's Answer #645675 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let x be in ten's place \n" ); document.write( "and y in unit's place\r \n" ); document.write( "\n" ); document.write( "the number is 10x+y\r \n" ); document.write( "\n" ); document.write( "10x+y = (x+y) *7 +3 \n" ); document.write( "10x+y = 7x+7v+3\r \n" ); document.write( "\n" ); document.write( "3x-6y = 3 \n" ); document.write( "/3 \n" ); document.write( "x-2y=1.........................(1)\r \n" ); document.write( "\n" ); document.write( "Digits interchanged , number will be 10y+x\r \n" ); document.write( "\n" ); document.write( "10y+x = 8(x-y)+1 \n" ); document.write( "10y+x=8x-8y+1 \n" ); document.write( "18y-7x=1.........................(2)\r \n" ); document.write( "\n" ); document.write( "Multiply (1) by 7 and add it to (2) \n" ); document.write( "7x-14y=7 \n" ); document.write( "18y-7x=1\r \n" ); document.write( "\n" ); document.write( "4y=8 \n" ); document.write( "y=2\r \n" ); document.write( "\n" ); document.write( "Now x-2y=1\r \n" ); document.write( "\n" ); document.write( "plug y\r \n" ); document.write( "\n" ); document.write( "x-4=1 \n" ); document.write( "x=5\r \n" ); document.write( "\n" ); document.write( "The number is 52\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |