document.write( "Question 1030876: Renee rows a boat downstream for 27 miles. The return trip upstream took 24 hours longer. If the current flows at 4 mph, how fast does Renee row in still water? \n" ); document.write( "
Algebra.Com's Answer #645660 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Renee rows a boat downstream for 27 miles. The return trip upstream took 24 hours longer.
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document.write( "Let \"u\" be Renee's boat speed in still water, in mph.\r\n" );
document.write( "Then the effective speed downstream is  (u + 4)  mph  (the speed relative to the river's bank).\r\n" );
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document.write( "The effective speed upstream is  (u - 4)  mph  (the speed relative to the river's bank).\r\n" );
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document.write( "The time spent moving downstream is  \"27%2F%28u%2B4%29\" hours.\r\n" );
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document.write( "The time spent moving   upstream is  \"27%2F%28u-4%29\" hours.\r\n" );
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document.write( "The condition says that\r\n" );
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document.write( "\"27%2F%28u-4%29\" - \"27%2F%28u%2B4%29\" = 24.\r\n" );
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document.write( "To solve this equation, multiply both sides by (u-4)*(u+4). You will get\r\n" );
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document.write( "27*(u+4) - 27*(u-4) = 24*(u-4)*(u+4).\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "\"27u+%2B+108+-+27u+%2B+108\" = \"24%2A%28u%5E2+-+16%29\",\r\n" );
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document.write( "\"216\" = \"24u%5E2+-+384\",\r\n" );
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document.write( "\"24u%5E2\" = \"216+%2B+384\",\r\n" );
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document.write( "\"24u%5E2\" = \"600\",\r\n" );
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document.write( "\"u%5E2\" = \"600%2F24\" = \"25\",\r\n" );
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document.write( "u = \"sqrt%2825%29\" = 5 mph.\r\n" );
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document.write( "Answer. Renee's boat speed in still water is  5  mph.\r\n" );
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document.write( "Check.  Time downstream \"27%2F%285%2B4%29\" =  3 h.  Time upstream   \"27%2F%285-4%29\" = 27 h.  Time difference 27 h - 3 h = 24 h.\r\n" );
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