document.write( "Question 1030915: We have three different mixtures of antifreeze and water. One mixture is 15% antifreeze, the second is 20% antifreeze and the third is 25% antifreeze, We would like to have 350 quarts of 19.5% antifreeze and use twice as much of the second mixture as the combined total of the first and third. How much of each mixture must we use? \r
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Algebra.Com's Answer #645659 by josgarithmetic(39625) $\"\"$ $\"About$

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document.write( "L     low     15%\r\n" );
document.write( "m     medium  20%\r\n" );
document.write( "h     high    25%

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\n" ); document.write( "\n" ); document.write( "Twice as much of the 20% as the combined quantities of the 15% and 25%.
\n" ); document.write( " $\"highlight_green%28m=2%28L%2Bh%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "ACCOUNT VOLUME OF MIX
\n" ); document.write( " $\"L%2Bm%2Bh=350\"$ , in unit of quarts.\r
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\n" ); document.write( "\n" ); document.write( "ACCOUNT CONCENTRATION OF MIX
\n" ); document.write( " $\"%2815L%2B20m%2B25h%29%2F350=19.5\"$ , both members in percent.\r
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\n" ); document.write( "\n" ); document.write( "Next in the process should be substitute for m in both accounting equations, and simplify each of these equations; and solve the resulting two-variable system of the two equations, using variables, L and h. \n" ); document.write( "

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