document.write( "Question 1030858: Michelle is 21 years older than her brother Frank. Nine years from now, Michelle will be twice as old as Frank. How old is each at the present time? \n" ); document.write( "
Algebra.Com's Answer #645625 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call their ages NOW, m and f. Then we write \n" ); document.write( "m = f + 21 \n" ); document.write( "Nine years from now, \n" ); document.write( "m + 9 = 2(f + 9) \n" ); document.write( "Substitute the first one into the second and get \n" ); document.write( "f+21 + 9 = 2(f + 9) \n" ); document.write( "f + 30 = 2f + 18 \n" ); document.write( "Now subtract 18 and subtract f and get \n" ); document.write( "f + 12 = 2f \n" ); document.write( "f = 12 \n" ); document.write( "Thus Michelle is 33. \n" ); document.write( " |