document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030797>Question 1030797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a linear equation is given by y=-3x+5. Find the equation of a line which is parallel to it and passes through the point(-2,-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645604 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "y = -3x + 5<BR>\n" );
document.write( "Lines that are parallel have<BR>\n" );
document.write( "the same gradient (slope)<BR>\n" );
document.write( "(m1 = m2)<BR>\n" );
document.write( "Using the gradient -3<BR>\n" );
document.write( "from the line at the top.<BR>\n" );
document.write( "Using the line equation:-<BR>\n" );
document.write( "y - b = m(x - a)<BR>\n" );
document.write( "m = -3<BR>\n" );
document.write( "(-2,-1) = (a,b)<BR>\n" );
document.write( "y -(-1) = -3(x - (-2))<BR>\n" );
document.write( "y + 1 = -3(x + 2)<BR>\n" );
document.write( "y + 1 = -3x - 6<BR>\n" );
document.write( "y = -3x - 6 - 1<BR>\n" );
document.write( "y = -3x - 7.<BR>\n" );
document.write( "This is the equation.<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );