document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030784>Question 1030784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of cream containing 12% butterfat must be added to 1500 grams of milk containing 2% butterfat to obtain milk having 4% butterfat? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645566 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> - How many grams of cream containing 12%: Let the amount be x<BR>\n" );
document.write( "- added to 1500 containing 2%: this will be 1500-x<BR>\n" );
document.write( "-  to obtain 1500 at 4%: this will be 0.04(1500)<BR>\n" );
document.write( "We have so far: <BR>\n" );
document.write( "0.12x+0.02(1500-x) = 0.04(1500)<BR>\n" );
document.write( "0.12x+30-0.02x = 60<BR>\n" );
document.write( "0.10x = 30<BR>\n" );
document.write( "x = 300 You have to add 300 grams of 12% </SPAN>\n" );
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