document.write( "Question 1030735: Jeremy has a bag of peanuts. He is going to share them so he counts them out. First he uses groups of 2, then groups of 3, 5 and 8, but each time there is 1 peanut left. How many are in the bag? Is there more than one answer?\r
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document.write( "Please give me some ideas to solve this problem. Thanks !
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Algebra.Com's Answer #645550 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2, then groups of 3, 5 and 8, but each time there is 1 peanut left.\r \n" ); document.write( "\n" ); document.write( "The number of peanuts must be 1 more than the multiples of all the above \r \n" ); document.write( "\n" ); document.write( "2*3*5*8 = 120 \r \n" ); document.write( "\n" ); document.write( "121 peanuts is one possibility\r \n" ); document.write( "\n" ); document.write( "You can form groups if you have 1 more than any multiple of 120 which is the LCM\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |