document.write( "Question 1030765: how do i solve:\r
\n" ); document.write( "\n" ); document.write( "if y=2 2/3 when x=1/4 find y when x=1 1/8\r
\n" ); document.write( "\n" ); document.write( "im not sure what category direct variation is under but some help would be great thank you :)
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Algebra.Com's Answer #645546 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "If y = 2 2/3 when x = 1/4
\n" ); document.write( "2 2/3 = 8/3
\n" ); document.write( "x = 1/4 when y = 8/3
\n" ); document.write( "Divide both by 1/4
\n" ); document.write( "x = 1 when y = 32/3
\n" ); document.write( "When x = 1 1/8 = 9/8
\n" ); document.write( "y = 32/3 x 9/8
\n" ); document.write( "y = 12.
\n" ); document.write( "Hope this helps :-)
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