document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030760>Question 1030760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The center of a circle is at (2,-5), one point on the circle is (-4,2).Find the other end of the diameter through (-4,2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645543 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=%28%28-4-2%29%5E2%2B%282-%28-5%29%29%5E2%29 ALIGN=MIDDLE  ALT=\"r%5E2=%28%28-4-2%29%5E2%2B%282-%28-5%29%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=%2836%2B49%29 ALIGN=MIDDLE  ALT=\"r%5E2=%2836%2B49%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=%2885%29 ALIGN=MIDDLE  ALT=\"r%5E2=%2885%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2%2B%28y%2B5%29%5E2=85 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2%2B%28y%2B5%29%5E2=85\"   DISABLED_style= \"max-width:90%; height:auto;\" >------but not really what you need.\r<BR>\n" );
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document.write( "The distance from center to any point on the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2885%29 ALIGN=MIDDLE  ALT=\"sqrt%2885%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "The center, and the endpoints for any of the diameters of the circle, are collinear.\r<BR>\n" );
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document.write( "The line containing this diameter contains the points  (2,-5) and (-4,2).  Using point-slope form, the equation for this line is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2B5=%28%282%2B5%29%2F%28-4-2%29%29%28x-2%29 ALIGN=MIDDLE  ALT=\"y%2B5=%28%282%2B5%29%2F%28-4-2%29%29%28x-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2B5=-%287%2F8%29%28x-2%29 ALIGN=MIDDLE  ALT=\"y%2B5=-%287%2F8%29%28x-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-%287%2F8%29x%2B14%2F8-5 ALIGN=MIDDLE  ALT=\"y=-%287%2F8%29x%2B14%2F8-5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-%287%2F8%29x%2B7%2F4-5 ALIGN=MIDDLE  ALT=\"y=-%287%2F8%29x%2B7%2F4-5\"   DISABLED_style= \"max-width:90%; height:auto;\" >......<BR>\n" );
document.write( "upon further thinking, this approach seems more complicated than necessary.\r<BR>\n" );
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document.write( "The center (2,-5)  is the MIDPOINT between the two endpoints for the diameter; and one endpoint is given to be  (-4,2).  The unknown endpoint is some ordered pair  (x,y).  Setup the midpoint formula for the circle's center and the two endpoints.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28%28x%2B%28-4%29%29%2F2=2%2C%28y%2B2%29%2F2=-5%29 ALIGN=MIDDLE  ALT=\"system%28%28x%2B%28-4%29%29%2F2=2%2C%28y%2B2%29%2F2=-5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28x-4=2%2A2%2Cy%2B2=-10%29 ALIGN=MIDDLE  ALT=\"system%28x-4=2%2A2%2Cy%2B2=-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28x=8%2Cand%2Cy=-12%29 ALIGN=MIDDLE  ALT=\"system%28x=8%2Cand%2Cy=-12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The other diameter's endpoint is  (8,-12). </SPAN>\n" );
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