document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030753>Question 1030753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three numbers added together total 180. The second number is twice the first and the third is three times the first. find each number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645537 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z = 180 (1)<BR>\n" );
document.write( "y = 2x<BR>\n" );
document.write( "z = 3x<BR>\n" );
document.write( "Substitute in (1)<BR>\n" );
document.write( "x+2x+3x = 180<BR>\n" );
document.write( "6x = 180<BR>\n" );
document.write( "x = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );