document.write( "Question 1030756: the width of a rectangle is one-fifth as much as the length. the perimeter is 120cm . Find the length and width \n" ); document.write( "
| Algebra.Com's Answer #645535 by addingup(3677)     You can put this solution on YOUR website! W = 1/5L \n" ); document.write( "Perimeter: \n" ); document.write( "2W+2L = 120 Substitute for W: \n" ); document.write( "2(1/5L)+2L = 120 \n" ); document.write( "2/5L+2L = 120 multiply both sides times 5 \n" ); document.write( "2L+10L = 600 \n" ); document.write( "12L = 600 \n" ); document.write( "L = 50 \n" ); document.write( "And: \n" ); document.write( "W = \n" ); document.write( "````````````````````````````````````` \n" ); document.write( "Check: \n" ); document.write( "Perimeter: \n" ); document.write( "2W+2L = 2(50)+2(10) = 120 Correct \n" ); document.write( " |