document.write( "Question 1030756: the width of a rectangle is one-fifth as much as the length. the perimeter is 120cm . Find the length and width \n" ); document.write( "
Algebra.Com's Answer #645535 by addingup(3677)\"\" \"About 
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W = 1/5L
\n" ); document.write( "Perimeter:
\n" ); document.write( "2W+2L = 120 Substitute for W:
\n" ); document.write( "2(1/5L)+2L = 120
\n" ); document.write( "2/5L+2L = 120 multiply both sides times 5
\n" ); document.write( "2L+10L = 600
\n" ); document.write( "12L = 600
\n" ); document.write( "L = 50
\n" ); document.write( "And:
\n" ); document.write( "W = \"1%2F5%2A50+=+50%2F5+=+10\"
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\n" ); document.write( "Check:
\n" ); document.write( "Perimeter:
\n" ); document.write( "2W+2L = 2(50)+2(10) = 120 Correct
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