document.write( "Question 1030715: Darius went on a bike ride of 48 miles. He realized that if he had gone 6 mph faster, he would have arrived 18 hours sooner. How fast did he actually ride?
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Algebra.Com's Answer #645518 by stanbon(75887) $\"\"$ $\"About$

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Darius went on a bike ride of 48 miles. He realized that if he had gone 6 mph faster, he would have arrived 18 hours sooner. How fast did he actually ride?
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\n" ); document.write( "slower speed DATA:
\n" ); document.write( "dist = 48 miles ; rate = x mph ; time = d/r = 48/x hrs
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\n" ); document.write( "faster speed DATA:
\n" ); document.write( "dist = 48 miles ;; rate = x+6 mph ; time = d/r = 48/(x+6) hrs
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\n" ); document.write( "slower time - faster time = 18 hr
\n" ); document.write( "48/x - 48/(x+6) = 18
\n" ); document.write( "48*(x+6) - 48x = 18x(x+6)
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\n" ); document.write( " 48*6 = 18x^2 + 108x
\n" ); document.write( "18x^2 + 108x - 288 = 0
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\n" ); document.write( "9x^2 + 54x - 144 = 0
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\n" ); document.write( "(x-2)(9x +72) = 0
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\n" ); document.write( "Ans: x = 2 mph (slower speed)
\n" ); document.write( "x+6 = 8 mph (faster speed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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