document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030631>Question 1030631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645496 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Picture an isosceles right triangle for starters...the sides of the triangle are 8/sqrt(2) = 4*sqrt(2).  But that is a 90 degree angle...you need a touch less...would make the sides a touch bigger...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Asqrt%282%29+=+5.6568 ALIGN=MIDDLE  ALT=\"4%2Asqrt%282%29+=+5.6568\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "so to the nearest tenth, the sides would have to be 5.7 cm each. </SPAN>\n" );
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