document.write( "Question 1030628: How to solve: Given the area of a rhombus is 24 cm2 and
\n" ); document.write( "its perimeter is 20 cm., what is its height? \n" ); document.write( "

Algebra.Com's Answer #645472 by Edwin McCravy(20055) $\"\"$ $\"About$

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document.write( "Here's another way, that doesn't require any special formulas\r\n" );
document.write( "involving diagonals, just the ordinary formulas for the area of a \r\n" );
document.write( "triangle and a rectangle.\r\n" );
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document.write( "Since the perimeter is 20 cm, and all 4 sides are the same length,\r\n" );
document.write( "each side is 20/4 = 5 cm each.  So we have this figure:\r\n" );
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document.write( "The rhombus is made up of two congruent right triangles\r\n" );
document.write( "plus a rectangle between them as we can see in the figure \r\n" );
document.write( "above.\r\n" );
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document.write( "Since all the sides are 5 cm each we have the equation:\r\n" );
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document.write( "The area of the rhombus is twice the area of one of the\r\n" );
document.write( "triangles plus the area of the rectangle in the middle.\r\n" );
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document.write( "The area of one of the triangles is \r\n" );
document.write( "So twice that is \r\n" );
document.write( "The area of the rectangle in the middle is .\r\n" );
document.write( "Therefore the area of the rhombus, which we set = 24, is\r\n" );
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document.write( "Since \r\n" );
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document.write( "we can substitute 5 for (x+y) and get:\r\n" );
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document.write( " or 4.8 cm.\r\n" );
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document.write( "Edwin

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