document.write( "Question 1030566: 5y^1/2+y^1/4-22=0 \n" ); document.write( "

Algebra.Com's Answer #645471 by fractalier(6550) $\"\"$ $\"About$

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From $\"5y%5E%281%2F2%29%2By%5E%281%2F4%29-22=0\"$
\n" ); document.write( "let us substitute x for y^(1/4) for now...we get
\n" ); document.write( " $\"5x%5E2+%2B+x+-+22+=+0\"$
\n" ); document.write( "Factoring we get
\n" ); document.write( " $\"%285x+%2B+11%29%28x+-+2%29+=+0\"$
\n" ); document.write( "which leads to
\n" ); document.write( "x = -11/5 and x = 2
\n" ); document.write( "Now back-subtitute and get
\n" ); document.write( "y^(1/4) = -11/5
\n" ); document.write( "y = (-11/5)^4
\n" ); document.write( "and
\n" ); document.write( "y^(1/4) = 2
\n" ); document.write( "y = 16
\n" ); document.write( "The second solution is best. \n" ); document.write( "

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