document.write( "Question 1030616: Mikayla went on a 48 mile trip to a soccer game. On the way back, due to road construction she had to drive 24 miles per hour slower. This made the trip take 1 hour longer. How fast did she drive to the soccer game? \n" ); document.write( "
Algebra.Com's Answer #645457 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the returning speed be x mph \n" ); document.write( "going to game speed = x+24\r \n" ); document.write( "\n" ); document.write( "Distance = 48 \n" ); document.write( " 1 hour more while returning\r \n" ); document.write( "\n" ); document.write( "time return - time going = 1\r \n" ); document.write( "\n" ); document.write( "48/x - 48/(x+24)=1\r \n" ); document.write( "\n" ); document.write( "LCD= x ( x + 24 ) \n" ); document.write( "multiply by LCD \n" ); document.write( "48 ( x + 24 ) - 48 x = 1 x ( x + 24 ) \n" ); document.write( "48 x + 1152 - 48 x = 1 X^2 + 24 x \n" ); document.write( "1152 = 1 X^2 - 24 x \n" ); document.write( " X^2 + 24 x -1152 = 0 \n" ); document.write( "x^2 +48x-24x-1152=0\r \n" ); document.write( "\n" ); document.write( "x(x+48)-24(x+48)=0\r \n" ); document.write( "\n" ); document.write( "(x-24)(x+48)=0\r \n" ); document.write( "\n" ); document.write( "x=-48 OR 24\r \n" ); document.write( "\n" ); document.write( "x =24 \n" ); document.write( "24 km/h while returning\r \n" ); document.write( "\n" ); document.write( "while going speed = 24+24 = 48 km/h \n" ); document.write( " \n" ); document.write( " |