document.write( "Question 1030520: Find all solutions in the interval [0, 2π). cosθcos2θ+sinθsin2θ= sqrt2/2
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Algebra.Com's Answer #645446 by ikleyn(52788)\"\" \"About 
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document.write( "Use the formula  \"cos%28alpha-beta%29\" = \"cos%28alpha%29%2Acos%28beta%29+%2B+sin%28alpha%29%2Asin%28beta%29\"\r\n" );
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document.write( "(see, for example, the lesson Addition and subtraction formulas in this site).\r\n" );
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document.write( "It gives you \r\n" );
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document.write( "\"cos%28theta%29%2Acos%282theta%29+%2B+sin%28theta%29%2Asin%282theta%29\" = \"cos%28theta-2theta%29\" = \"cos%28-theta%29\".\r\n" );
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document.write( "So, your original equation becomes\r\n" );
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document.write( "\"cos%28-theta%29\" = \"sqrt%282%29%2F2\".   (1)\r\n" );
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document.write( "Since  \"cos%28-theta%29\"  is always equal to  \"cos%28theta%29\", you can rewrite (1) in the form\r\n" );
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document.write( "\"cos%28theta%29\" = \"sqrt%282%29%2F2\".   (2)\r\n" );
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document.write( "The equation (2) has two and only two solutions in the given interval.\r\n" );
document.write( "They are  \"theta\" = \"pi%2F4\"  and/or  \"theta\" = \"7pi%2F4\".\r\n" );
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