document.write( "Question 1030384: Bob incorrectly reasons that logb 1/x= logb x/xx
\n" ); document.write( " Bob's answer- =logb x-logb x+logb x=logb x.
\n" ); document.write( "What mistake has Bob made?
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Algebra.Com's Answer #645378 by JoelSchwartz(130)\"\" \"About 
You can put this solution on YOUR website!
log b (x) - log b (x) + log b (x) = log b (x)
\n" ); document.write( "x/x + log b (x) = log b (x)
\n" ); document.write( "1 = log b (x) - log b (x)
\n" ); document.write( "Bob has not solved that log b (1/x) = log b (x/x^2)
\n" ); document.write( "he has only solved x/x equals one
\n" ); document.write( "to solve this equation here is the work required
\n" ); document.write( "log b (1) - log b (x) = log b (x) - log b (x^2)
\n" ); document.write( "log b (1) = log b (x) + log b (x) - log b (x^2)
\n" ); document.write( "log b (1) = log b (x^2) - log b (x^2)
\n" ); document.write( "(x^2)/(x^2)=1
\n" ); document.write( "x^2=x^2
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