document.write( "Question 1030468: please help me solve this question:
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document.write( "clatheria is 40 years elder than clare. 5 years ago clatheria was 3 times as old as clare. what is their age now? \n" );
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Algebra.Com's Answer #645332 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call Clatheria's and Clare's ages NOW, x and y, respectively. \n" ); document.write( "Then we write \n" ); document.write( "x = y + 40 \n" ); document.write( "Five years ago \n" ); document.write( "x - 5 = 3(y - 5) \n" ); document.write( "Now substitute and get \n" ); document.write( "y+40 - 5 = 3(y - 5) \n" ); document.write( "y + 35 = 3y - 15 \n" ); document.write( "Add 15 and subtract y and get \n" ); document.write( "y + 50 = 3y \n" ); document.write( "2y = 50 \n" ); document.write( "y = 25 (Clare) and then \n" ); document.write( "x = y + 40 = 65 (Clatheira) \n" ); document.write( " |