document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030464>Question 1030464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by substitution y=2x+1 the second part is 3x+y=11, I know that the formula for x is 3x+(2x+1)=11, that then becomes 5x+1=11 subtract 1 from both sides and you get 5x=10 which comes out to x=2 so the x coordinate is 2 i don't know how to find the y coordinate </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645325 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=2 <BR>\n" );
document.write( "Now put back into either part<BR>\n" );
document.write( "y=2x+1<BR>\n" );
document.write( "y=2(2)+1=5<BR>\n" );
document.write( "check with the other equation (2,5): 3(2)+5=11<BR>\n" );
document.write( "(2,5) is the answer. </SPAN>\n" );
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