document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030285>Question 1030285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lateral area. <BR>\n" );
document.write( "The circumference of a sphere is 56.55yd </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645311 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well the surface area of a sphere is found by<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+4%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"A+=+4%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If the circumference is 56.55, we can find r...<BR>\n" );
document.write( "C = 2(pi)r<BR>\n" );
document.write( "2(pi)r = 56.55<BR>\n" );
document.write( "2r = 18<BR>\n" );
document.write( "r = 9<BR>\n" );
document.write( "Now plug in above and get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+4%28pi%29%2A9%5E2+=+324%28pi%29+=+1017.88 ALIGN=MIDDLE  ALT=\"A+=+4%28pi%29%2A9%5E2+=+324%28pi%29+=+1017.88\"   DISABLED_style= \"max-width:90%; height:auto;\" > square yards </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );