document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030415>Question 1030415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by substitution y=2x+1 the second part is 3x+y=11  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645302 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let us solve this one for you...<BR>\n" );
document.write( "y=2x+1 <BR>\n" );
document.write( "3x+y=11<BR>\n" );
document.write( "Plugging the first one into the second gives you<BR>\n" );
document.write( "3x + (2x+1) = 11<BR>\n" );
document.write( "3x + 2x + 1 = 11<BR>\n" );
document.write( "5x + 1 = 11<BR>\n" );
document.write( "Now sbtract one and divide by five and get<BR>\n" );
document.write( "5x = 10<BR>\n" );
document.write( "x = 2 so that<BR>\n" );
document.write( "y = 2(2) + 1 = 4 + 1 = 5<BR>\n" );
document.write( "(2, 5) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );