document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030442>Question 1030442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the hypotenuse of 30-60-90 a triangle is 4. What is the perimeter?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645290 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of the hypotenuse of 30-60-90 a triangle is 4. What is the perimeter?<BR>\n" );
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document.write( "If side opposite 30 deg = 1<BR>\n" );
document.write( "Then hypotenuse = 2<BR>\n" );
document.write( "And 3rd side = sqrt(2^2-1^2) = sqrt(3)<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "If hypot = 4, then side opposite 30 = 2, and 3rd side is 2sqrt(3)<BR>\n" );
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document.write( "Perimeter = 4 + 2 + 2sqrt(3) = 6 + 2sqrt(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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