document.write( "Question 1030369: -sin(π/2-x)=√3*sin(x)\r
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Algebra.Com's Answer #645230 by ikleyn(52814)\"\" \"About 
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document.write( "1.  \"-sin%28pi%2F2-x%29\" = \"-cos%28x%29\".\r\n" );
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document.write( "2.  Therefore, the original equation takes the form\r\n" );
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document.write( "    \"-cos%28x%29\" = \"sqrt%283%29%2Asin%28x%29\".\r\n" );
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document.write( "3.  Then  \"sin%28x%29%2Fcos%28x%29\" = \"-1%2Fsqrt%283%29\",   or\r\n" );
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document.write( "    \"tan%28x%29\" = \"-sqrt%283%29%2F3\".\r\n" );
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document.write( "    x = \"5pi%2F6\",  or  150°.\r\n" );
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