document.write( "Question 1030369: -sin(π/2-x)=√3*sin(x)\r
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document.write( "(0≤x<π)
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Algebra.Com's Answer #645230 by ikleyn(52814)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "-sin(pi/2-x) = sqrt(3)*sin(x)\r \n" ); document.write( "\n" ); document.write( "(0 <= x < pi) \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "1. \n" ); document.write( " \n" ); document.write( " |