document.write( "Question 1030353: Use Calculus. For what value of a is the following equation true?\r
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Algebra.Com's Answer #645228 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"%28%28x%2Ba%29%2F%28x-a%29%29%5Ex\"\"%22%22=%22%22\"\"e\"\r\n" );
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document.write( "That will be true if and only if the \r\n" );
document.write( "limit of the natural log is 1, so we\r\n" );
document.write( "reduce the problem to finding \"a\" if\r\n" );
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"ln%28%28%28x%2Ba%29%2F%28x-a%29%29%5Ex%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"x%2Aln%28%28x%2Ba%29%2F%28x-a%29%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"ln%28%28x%2Ba%29%2F%28x-a%29%29%2F%281%2Fx%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "Since \"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"%28%28x%2Ba%29%2F%28x-a%29%29\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "therefore \"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"ln%28%28x%2Ba%29%2F%28x-a%29%29\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "And also \"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"%281%2Fx%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "Both numerator and denominator approach 0, so\r\n" );
document.write( "we can use L'Hopital's rule\r\n" );
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"%28%282a%2F%28a%5E2-x%5E2%29%29%2F%28-1%2Fx%5E2%29%29%29\" = 1\r\n" );
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document.write( "which simplifes to\r\n" );
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document.write( "\"matrix%282%2C1%2Clim%2C%22x-%3Eoo%22%29\"\"%28-2ax%5E2%2F%28a%5E2-x%5E2%29%29%29\" = 1\r\n" );
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document.write( "That limit is \"2a\", so we have\r\n" );
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document.write( "\"2a+=+1\"\r\n" );
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document.write( "\"a+=+1%2F2\"\r\n" );
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document.write( "Edwin
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