document.write( "Question 1030335: Travis made a business trip of 234.5 miles. He averaged 53 mph for the first part of the trip and 51 mph for the second part. If the trip took 4.5 hours, how long did he travel at each rate? \n" ); document.write( "
Algebra.Com's Answer #645221 by ankor@dixie-net.com(22740)\"\" \"About 
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avis made a business trip of 234.5 miles.
\n" ); document.write( " He averaged 53 mph for the first part of the trip and 51 mph for the second part.
\n" ); document.write( " If the trip took 4.5 hours, how long did he travel at each rate?
\n" ); document.write( ":
\n" ); document.write( "Let t = time traveled at 53 mph
\n" ); document.write( "Total time is given as 4.5 hrs, therefore
\n" ); document.write( "(4.5-t) = time traveled at 51 mph
\n" ); document.write( ":
\n" ); document.write( "Write distance equation; dist = speed * time
\n" ); document.write( "53t + 51(4.5-t) = 234.5
\n" ); document.write( "53t + 229.5 - 51t = 234.5
\n" ); document.write( "53t - 51t = 234.5 - 229.5
\n" ); document.write( "2t = 5
\n" ); document.write( "t = 2.5 hrs at 53 mph,
\n" ); document.write( "then
\n" ); document.write( "4.5 - 2.5 = 2 hrs at 51 mph
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the actual dist at each speed
\n" ); document.write( "53(2.5) = 132.5 mi
\n" ); document.write( "51(2) = 102.0 mi
\n" ); document.write( "------------------
\n" ); document.write( "total dist: 234.5 \n" ); document.write( "
\n" );