document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030365>Question 1030365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of wire is decrease to one-third. If volume remains the same, the length become. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645209 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius of wire is decrease to one-third. If volume remains the same, the length become. <BR>\n" );
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document.write( "V = pi*r^2*h<BR>\n" );
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document.write( "Under changed conditions::<BR>\n" );
document.write( "V = pi*(1/3 r)^2*h<BR>\n" );
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document.write( "V = pi(r^2/9)h<BR>\n" );
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document.write( "h = 9V/(pi*r^2<BR>\n" );
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document.write( "Cheers<BR>\n" );
document.write( "Stan H.<BR>\n" );
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