document.write( "Question 88775: I am supposed to find the x intercept but am confused. Any help is appreciated.\r
\n" ); document.write( "\n" ); document.write( "y=x^2+x-6\r
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Algebra.Com's Answer #64520 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find the x-intercept, set y equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2Bx-6\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2Bx-6=0\" ( notice \"a=1\", \"b=1\", and \"c=-6\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+%281%29%5E2-4%2A1%2A-6+%29%29%2F%282%2A1%29\" Plug in a=1, b=1, and c=-6\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1-4%2A1%2A-6+%29%29%2F%282%2A1%29\" Square 1 to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%2B24+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-6%2A1\" to get \"24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+25+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+5%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+5%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B+5%29%2F2\" or \"x+=+%28-1+-+5%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-1+%2B+5%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=4%2F2\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-1+-+5%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2F2\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2Bx-6\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-13%2C+12%2C+-13%2C+12%2C1%2Ax%5E2%2B1%2Ax%2B-6%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=2\" and \"x=-3\". This verifies our answer
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