document.write( "Question 1030310: Hello!
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document.write( "My question is: The weights of ripe watermelons grown at Mr. Smith's farm are normally distributed with a standard deviation of 2.8 lbs. Find the mean weight of Mr.Smith's ripe watermelons if only 3% weigh less than 15lbs.\r
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document.write( "Thank you for your help!! \n" );
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Algebra.Com's Answer #645183 by mathmate(429) You can put this solution on YOUR website! \n" ); document.write( "Question: \n" ); document.write( "Hello! \n" ); document.write( "My question is: The weights of ripe watermelons grown at Mr. Smith's farm are normally distributed with a standard deviation of 2.8 lbs. Find the mean weight of Mr.Smith's ripe watermelons if only 3% weigh less than 15lbs. \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "This is a nice question that digs into the understanding of the Normal Distribution parameters. \n" ); document.write( "If only 3% weigh less than 15 lbs, then we can find the standard deviation from 3% using the normal distribution table or function: \n" ); document.write( "P(Z)=97%, Z=+1.8808. \n" ); document.write( "Since standard deviation is given as 2.8 lbs, so \n" ); document.write( "μ+1.8808*2.8=15 lbs, or \n" ); document.write( "μ=15-1.8808*2.8=15-5.27=9.73 lb. \n" ); document.write( "Ans. the mean weight is 9.73 lb. (approx.) \n" ); document.write( " |