document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030174>Question 1030174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> raoul has to finish a 473 page book in a week. he decides to read the same number of pages each weekday and 30 extra pages on saturday and on sunday. how many pages will he have to read on wednesday? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645141 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # of pages he has to read on a weekday.<BR>\n" );
document.write( "==> x + 30 =  # of pages he has to read on a Saturday or a Sunday.<BR>\n" );
document.write( "==> 5x + 2(x+30) = 473<BR>\n" );
document.write( "==> 5x + 2x + 60 = 473<BR>\n" );
document.write( "==> 7x = 413<BR>\n" );
document.write( "==> x = 59.\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, he has to read 59 pages on a weekday, particularly on Wednesday. </SPAN>\n" );
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