document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030258>Question 1030258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:\r<BR>\n" );
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document.write( "Andrew and Karen started at the same place and walked in opposite directions. Andrew walked at a speed of six kilometres an hour and Karen walked at a speed of four kilometres an hour. After they had walked for half an hour, what was the distance between them? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645136 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the formula \"rate(r) times time(t) = distance(d)\"<BR>\n" );
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document.write( "Andrew's rate is 6km/hr and Karen's is 4km/hr and they walked in opposite directions for 1/2 hour<BR>\n" );
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document.write( "we add their two distances<BR>\n" );
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document.write( "(6 * (1/2)) + (4 * (1/2)) = 3 + 2 = 5 <BR>\n" );
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document.write( "The distance between them is 5 Km<BR>\n" );
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