document.write( "Question 1030196: In a sample of 300 students what is the probability of seeing 32% of the students choosing sports when it is known that on an average 25% of the students go for the sports. It is assumed that selecting the sports is an independent event.
\n" ); document.write( " 0.99
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\n" ); document.write( " 0.001 or 0.002
\n" ); document.write( " Not enough information is given
\n" ); document.write( "I have used Poisson distribution =POISSON.DIST(96,75,FALSE) which gave me 0.002. Is this correct?
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Algebra.Com's Answer #645123 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
My scientific calculator is not powerful enough to evaluate \"%28matrix%282%2C1%2C+300%2C96%29%29%2A0.75%5E204%2A0.25%5E96\", which is the true answer.\r
\n" ); document.write( "\n" ); document.write( "If you're going to use the Poisson to approximate this, with \"lambda+=+np+=+300%2A0.25+=+75\", you would get
\n" ); document.write( "\"p%2896%29+=+%2875%5E96%2F96%21%29e%5E-75+=+0.002738\", to four significant figures.\r
\n" ); document.write( "\n" ); document.write( "I tried approximating using the normal distribution using \"p%280.315+%3C=+r+%3C=+0.325%29+=+p%282.6+%3C=+z+%3C=+3%29\", and I got 0.9987-0.9953 = 0.0034, so more or else the real value should be in the close neighborhood.
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