document.write( "Question 88711: I am not good at all with word problems and need some help\r
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Algebra.Com's Answer #64510 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " A passaenger train can travel 325 miles in the sametime a freight train takes to travel 200 miles. If the speed of the passenger train is 25 miles/h faster than the speed of the freight train . Find the speed for each.\r \n" ); document.write( "\n" ); document.write( " Let the speed of the frieght train be = x miles/hr \n" ); document.write( " Then the speed of the passenger train = x+25 miles/hr \n" ); document.write( "Distance travelled by frieght train is = 200 miles \n" ); document.write( " \n" ); document.write( "Distance travelled by passenger train is = 325 miles\r \n" ); document.write( "\n" ); document.write( " time taken by both the trains is same . \n" ); document.write( " therefore time taken by frieght train = time taken by passenger train \n" ); document.write( " \n" ); document.write( " time taken = distance travelled/speed\r \n" ); document.write( "\n" ); document.write( " i.e, 200/x = 325/(x+25)\r \n" ); document.write( "\n" ); document.write( " 200(x+25) = 325(x) \n" ); document.write( " 200x+5000 = 325x\r \n" ); document.write( "\n" ); document.write( " 325x-200x = 5000 \n" ); document.write( " 125x = 5000 or x = 5000/125 \n" ); document.write( " x = 40 miles/hr\r \n" ); document.write( "\n" ); document.write( " Therefore the speed of Frieght train = 40 miles/hr \n" ); document.write( " the speed of passenger train = 40+25 = 65 miles/hr \n" ); document.write( " |