document.write( "Question 88711: I am not good at all with word problems and need some help\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #64510 by malakumar_kos@yahoo.com(315)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( " A passaenger train can travel 325 miles in the sametime a freight train takes to travel 200 miles. If the speed of the passenger train is 25 miles/h faster than the speed of the freight train . Find the speed for each.\r
\n" ); document.write( "\n" ); document.write( " Let the speed of the frieght train be = x miles/hr
\n" ); document.write( " Then the speed of the passenger train = x+25 miles/hr
\n" ); document.write( "Distance travelled by frieght train is = 200 miles
\n" ); document.write( "
\n" ); document.write( "Distance travelled by passenger train is = 325 miles\r
\n" ); document.write( "\n" ); document.write( " time taken by both the trains is same .
\n" ); document.write( " therefore time taken by frieght train = time taken by passenger train
\n" ); document.write( "
\n" ); document.write( " time taken = distance travelled/speed\r
\n" ); document.write( "\n" ); document.write( " i.e, 200/x = 325/(x+25)\r
\n" ); document.write( "\n" ); document.write( " 200(x+25) = 325(x)
\n" ); document.write( " 200x+5000 = 325x\r
\n" ); document.write( "\n" ); document.write( " 325x-200x = 5000
\n" ); document.write( " 125x = 5000 or x = 5000/125
\n" ); document.write( " x = 40 miles/hr\r
\n" ); document.write( "\n" ); document.write( " Therefore the speed of Frieght train = 40 miles/hr
\n" ); document.write( " the speed of passenger train = 40+25 = 65 miles/hr
\n" ); document.write( "
\n" );