document.write( "Question 1030202: Solve the partial fraction decomposition of the rational expression:\r
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document.write( "(3x^2+49) / (x(x+7)^2) = (A/x) + (B/(x+7)) + (C/(x+7)^2)\r
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document.write( "Thank you for your help!! \n" );
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Algebra.Com's Answer #645094 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve the partial fraction decomposition of the rational expression: \n" ); document.write( "(3x^2+49) / (x(x+7)^2) = (A/x) + (B/(x+7)) + (C/(x+7)^2) \n" ); document.write( "-------------------------- \n" ); document.write( "Equate the numerators of the two sides:: \n" ); document.write( "3x^2 + 49 = A(x+7)^2 + B(x(x+7)) + Cx \n" ); document.write( "------- \n" ); document.write( "3x^2 + 49 = A(x^2+14x + 49) + B(x^2+7x) + Cx \n" ); document.write( "------- \n" ); document.write( "3x^2 + 49 = (A+B)x^2 + (14A +7B +C)x + 49A \n" ); document.write( "-------- \n" ); document.write( "Equate the proper coefficients: \n" ); document.write( "A+B = 3 \n" ); document.write( "14A + 7B + C = 0 \n" ); document.write( "49A = 49 \n" ); document.write( "---------- \n" ); document.write( "Solve for A, B, and C \n" ); document.write( "A = 1 \n" ); document.write( "B = 3-1 = 2 \n" ); document.write( "----- \n" ); document.write( "C = -14-14 = -28 \n" ); document.write( "------------------------ \n" ); document.write( "(3x^2+49) / (x(x+7)^2) = (A/x) + (B/(x+7)) + (C/(x+7)^2) \n" ); document.write( "---------------- \n" ); document.write( "(3x^2+49) / (x(x+7)^2) = = 1/x + 2/(x+7) - 28/(x+7)^2 \n" ); document.write( "-------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------\r \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "3x^2 + 49 = 1/(x+7)^2 + 2/ \n" ); document.write( " |