document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030204>Question 1030204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of twice a number and three times another number is 120. Four times the first number plus the second number is 64. Calculate the value of the two numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645092 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of twice a number and three times another number is 120. Four times the first number plus the second number is 64. Calculate the value of the two numbers.<BR>\n" );
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document.write( "Equations::<BR>\n" );
document.write( "2x + 3y = 120<BR>\n" );
document.write( "4x + y = 64<BR>\n" );
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document.write( "Modify for elimination:<BR>\n" );
document.write( "2x + 3y = 1203<BR>\n" );
document.write( "12x + 3y = 192<BR>\n" );
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document.write( "Subtract and solve for \"x\"::<BR>\n" );
document.write( "10x = 72<BR>\n" );
document.write( "x = 7.2<BR>\n" );
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document.write( "Solve for \"y\"::<BR>\n" );
document.write( "y = -4x + 64<BR>\n" );
document.write( "y = -28.8 + 64<BR>\n" );
document.write( "y = 35.2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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