document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88713>Question 88713</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64509 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "  A back yard has dimensions 3 4/5 yards by 1 1/2 yards. What is the area of the back yard in square yards?<BR>\n" );
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document.write( "  The dimensionsof the back yard = 3 4/5 yds  and 1 1/2 yds\r<BR>\n" );
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document.write( "     Area of th back yard        =  Product of their dimensions\r<BR>\n" );
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document.write( "                                 =( 3 4/5)(1 1/2)\r<BR>\n" );
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document.write( "                                 = (3*5+4) /5(1*2+1) /2<BR>\n" );
document.write( "                                 = (15+4)(2+1)/10<BR>\n" );
document.write( "                                 = 19*3/10<BR>\n" );
document.write( "                                 = 57/10<BR>\n" );
document.write( "                                 = 5.7 sq yds </SPAN>\n" );
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