document.write( "Question 88728This question is from textbook
\n" ); document.write( ": cn you please assist me with the following algebra problems\r
\n" ); document.write( "\n" ); document.write( "1.solved the system of linear equation by grphing.\r
\n" ); document.write( "\n" ); document.write( "4x-y=6
\n" ); document.write( "3x+y=1\r
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\n" ); document.write( "\n" ); document.write( "x+2y=5
\n" ); document.write( "x-y=2\r
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\n" ); document.write( "\n" ); document.write( "y=x2-4
\n" ); document.write( "y=x-2\r
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\n" ); document.write( "\n" ); document.write( "y=x2+5 and y=2x+4\r
\n" ); document.write( "\n" ); document.write( "thank you for your assistance \n" ); document.write( "
Algebra.Com's Answer #64508 by madhujiithcharu@yahoo.co.in(28)\"\" \"About 
You can put this solution on YOUR website!
For the above problems you first assume values ....,-2,-1,0,1,2.... for x. Substitute all the values one by on in the first equation and then in the second equation. You will get corresponding y values. Now you got two set of values. Then plot those points in graph a usual you will get proper solution.
\n" ); document.write( "For eg. consider the 2nd problme 4x-y = 6 , 3x+y=1
\n" ); document.write( " i.e, y=4x-6 , y=1-3x
\n" ); document.write( "If we take x=0 then y=-6 and y=1. So we get 2 sets of values (0,-6) and (0,1)
\n" ); document.write( " x=1 then y=-2 and y=-2. So we get (1,-2) and (1,-2)
\n" ); document.write( " x=-1 then y=-10 & y=4 . So (-1,-10) & (-1,4) Proceeding like this we get one set as (-1,-11),(0,-6),(1,-2),and so on.and (-1,4), (0,1), (1,-2) and so on. Plot them in graph you will get an intersecting point and that is the value of x and y. \n" ); document.write( "
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