document.write( "Question 1030170: The helicopter could fly at 4 times the speed of the wind. Thus, it could travel 600 miles downwind in 1 hour more than it took to travel 300 miles upwind. What was the speed of the helicopter in still air?
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Algebra.Com's Answer #645079 by MathTherapy(10552) $\"\"$ $\"About$

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The helicopter could fly at 4 times the speed of the wind. Thus, it could travel 600 miles downwind in 1 hour more than it took to travel 300 miles upwind. What was the speed of the helicopter in still air?
\n" ); document.write( "---I am not sure how this problem is solved. I have done other problems somewhat similar to this, but this is a bit more difficult. An explanation would be greatly appreciated. Thank you!
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Let the speed of the helicopter, in still air, be S
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document.write( "Then speed of wind = 
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document.write( "Time it took to travel downwind: 
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document.write( "Time it took to travel upwind:  
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document.write( "We then get: 
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document.write( " ----- Multiplying by LCD, 
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document.write( " 
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document.write( " ------- Multiplying by LCD, 16
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document.write( "S(S - 80) = 0
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document.write( "S or speed or helicopter, in still air = 	   OR	      S = 0 (ignore) \n" );
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