document.write( "Question 1030138: I have to solve 2log3x=4. (The 3 is subscript)
\n" ); document.write( "I took the 2 from in front and used it as the power to 3. 3 squared is 9 and I don't understand how that equals 4.
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Algebra.Com's Answer #645076 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "I have to solve 2log3x=4. (The 3 is subscript)
\n" ); document.write( "I took the 2 from in front and used it as the power to 3. 3 squared is 9 and I don't understand how that equals 4.
\n" ); document.write( "
\"2+%2A+log%283%2C+%28x%29%29+=+4\"\r\n" );
document.write( "\"log+%283%2C+%28x%29%29+=+4%2F2\" ------- Dividing both sides by 2\r\n" );
document.write( "\"log+%283+%28x%29%29+=2\"\r\n" );
document.write( "\"matrix%281%2C7%2C+x%2C+%22=%22%2C+3%5E2%2C+or%2C+x%2C+%22=%22%2C+9%29\" ------- Converting to EXPONENTIAL form\r\n" );
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document.write( "As seen, 9 is correct\r\n" );
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document.write( "Checking\r\n" );
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\"2+%2A+log+%283%2C+%28x%29%29+=+4\" \r\n" );
document.write( "\"2+%2A+log+%283%2C+%289%29%29+=+4\" ------ Substituting 9 for x \r\n" );
document.write( "2 * 2 = 4 ------ \"matrix%281%2C3%2C+log+%283%2C+%289%29%29%2C+%22=%22%2C+2%29\"
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