document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030171>Question 1030171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I use log_a(20)=1.4406 and log_a(5)=0.7740 to evaluate each expression.<BR>\n" );
document.write( "1. log_a(100) <BR>\n" );
document.write( "2. log_a 5^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645067 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How do I use log_a(20)=1.4406 and log_a(5)=0.7740 to evaluate each expression.<BR>\n" );
document.write( "1. log_a(100)<BR>\n" );
document.write( "100 = 5*20<BR>\n" );
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document.write( "Ans: loga(100) = loga(5) + loga(20) = 0.7740+1.4406 = 2.2146<BR>\n" );
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document.write( "2. log_a 5^3 = 3*loga(5) = 3*0.7740 = 3.3220<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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