document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030138>Question 1030138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to solve 2log3x=4. (The 3 is subscript)<BR>\n" );
document.write( "I took the 2 from in front and used it as the power to 3.  3 squared is 9 and I don't understand how that equals 4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645048 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equation is 2 * log3(x) = 4\r<BR>\n" );
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document.write( "this is equivalent to log3(x^2) = 4\r<BR>\n" );
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document.write( "this is true if and only if 3^4 = x^2\r<BR>\n" );
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document.write( "take the square root of both sides of this equation to get (3^4)^(1/2) = (x^2)^(1/2)\r<BR>\n" );
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document.write( "this becomes 3^2 = x\r<BR>\n" );
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document.write( "solve for x to get x = 9.\r<BR>\n" );
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document.write( "you can confirm that the solution is correct by replace x in the original equation and then evaluating that equation.\r<BR>\n" );
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document.write( "your original equation is 2 * log3(x) = 4\r<BR>\n" );
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document.write( "after you replace x with 9, this equation becomes 2 * log3(9) = 4\r<BR>\n" );
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document.write( "if you divide both sides of this equation by 2, you get log3(9) = 2\r<BR>\n" );
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document.write( "you can use the log base conversion formula to find log3(9).\r<BR>\n" );
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document.write( "log3(9) is equal to log10(9)/log10(3).\r<BR>\n" );
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document.write( "the log function of your calculator gives you log10.\r<BR>\n" );
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document.write( "the log base conversiion formula also gets you:\r<BR>\n" );
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document.write( "log3(9) = ln(9)/ln(3).\r<BR>\n" );
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document.write( "the ln function of your calculator gives you that.\r<BR>\n" );
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document.write( "in your calculator, do log(9)/log(3) and you will get 2.\r<BR>\n" );
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document.write( "in your calculator, do ln(9)/ln(3) and you will get 2.\r<BR>\n" );
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document.write( "here's some tutorials that may help you.\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF= \"http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/index.htm\" target = \"_blank\">http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/index.htm</a>\r<BR>\n" );
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document.write( "tutorials 42 through 48 deal with logarithmic equations and exponential equations which is what you are dealing with.\r<BR>\n" );
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document.write( "there's also lots of other good tutorials up there that may be helpful to you as well.\r<BR>\n" );
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document.write( "if you have any specific questions you still need to know about  how to solve this problem, send me an email and i'll try to explain further.\r<BR>\n" );
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document.write( "the basic log formulas that you would be using on this problem are:\r<BR>\n" );
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document.write( "a * log(b) = log(b^a)\r<BR>\n" );
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document.write( "logb(a) = c if and only if b^c = a\r<BR>\n" );
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