document.write( "Question 1030149: solve by substitution x=y-2 the second part is 4x+y=12, answer using (___,___) \n" ); document.write( "

Algebra.Com's Answer #645046 by Cromlix(4381) $\"\"$ $\"About$

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Hi there,
\n" ); document.write( "x = y - 2..........(1)
\n" ); document.write( "4x + y = 12........(2)
\n" ); document.write( "Substitute x = y - 2 from
\n" ); document.write( "Eq(1) into Eq(2)
\n" ); document.write( "4x + y = 12
\n" ); document.write( "4(y - 2)+ y = 12
\n" ); document.write( "Multiply out
\n" ); document.write( "4y - 8 + y = 12
\n" ); document.write( "Collect like terms:
\n" ); document.write( "4y + y = 12 + 8
\n" ); document.write( "5y = 20
\n" ); document.write( "y = 4
\n" ); document.write( "Substitute y = 4 into
\n" ); document.write( "Eq(1)
\n" ); document.write( "x = y - 2
\n" ); document.write( "x = 4 - 2)
\n" ); document.write( "x = 2
\n" ); document.write( "(2,4)
\n" ); document.write( "Hope this helps :-)
\n" ); document.write( " \n" ); document.write( "

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