document.write( "Question 1030069: The speed of a moving sidewalk at an airport is
\n" ); document.write( "66
\n" ); document.write( "​ft/sec. A person can walk
\n" ); document.write( "3838
\n" ); document.write( "ft forward on the moving sidewalk in the same time it takes to walk
\n" ); document.write( "1010
\n" ); document.write( "ft on a nonmoving sidewalk in the opposite direction. At what rate would a person walk on a nonmoving​ sidewalk?
\n" ); document.write( "

Algebra.Com's Answer #645033 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The speed of a moving sidewalk at an airport is 66​ft/sec.
\n" ); document.write( "A person can walk 3838 ft forward on the moving sidewalk in the same time it takes to walk 1010 ft on a nonmoving sidewalk in the opposite direction.
\n" ); document.write( " At what rate would a person walk on a nonmoving​ sidewalk?
\n" ); document.write( ":
\n" ); document.write( "let r = his rate walking on a non-moving sidewalk
\n" ); document.write( "then
\n" ); document.write( "(r+66) = his rate forward on moving sidewalk
\n" ); document.write( ":
\n" ); document.write( "write a time equation; time = dist/speed
\n" ); document.write( "\"1010%2Fr\" = \"3838%2F%28%28r%2B66%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3838r = 1010(r+66)
\n" ); document.write( "3838r = 1010r + 66660
\n" ); document.write( "3838r - 1010r = 66660
\n" ); document.write( "r = 66660/2828
\n" ); document.write( "r = 23.57 ft/sec
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this, find the actual time of each scenario
\n" ); document.write( "\"1010%2F23.57\" = 42.85 sec
\n" ); document.write( "\"3838%2F%28%2823.57%2B66%29%29\" = 42.85 sec
\n" ); document.write( "
\n" ); document.write( "
\n" );